library IEEE;

use IEEE.std_logic_1164.all;

entity bejoy_fa is

port(In1,In2,c_in : in std_logic;

sum, c_out : out std_logic);

end bejoy_fa;

architecture arc of bejoy_fa is

component half_adder

port(a,b : in std_logic;

sum, carry : out std_logic);

end component;

component or_2

port(a,b : in std_logic;

c : out std_logic);

end component;

signal s1, s2, s3 : std_logic;

begin

H1: half_adder port map(a=>In1, b=>In2, sum=>s1, carry=>s3);

H2: half_adder port map(a=>s1, b=>c_in, sum=>sum, carry=>s2);

O1: or_2 port map(a=> s2, b=>s3, c=>c_out);

end arc;

entity half_adder is

port (a,b : in bit ;

sum,carry : out bit);

end half_adder;

architecture arc of half_adder is

begin

sum<= a xor b;

carry <= a and b;

end arc;

entity or_2 is

port (a,b : in bit ;

c : out bit);

end or_2;

architecture arc of or_2 is

begin

c<= a or b;

end arc;

use IEEE.std_logic_1164.all;

entity bejoy_fa is

port(In1,In2,c_in : in std_logic;

sum, c_out : out std_logic);

end bejoy_fa;

architecture arc of bejoy_fa is

component half_adder

port(a,b : in std_logic;

sum, carry : out std_logic);

end component;

component or_2

port(a,b : in std_logic;

c : out std_logic);

end component;

signal s1, s2, s3 : std_logic;

begin

H1: half_adder port map(a=>In1, b=>In2, sum=>s1, carry=>s3);

H2: half_adder port map(a=>s1, b=>c_in, sum=>sum, carry=>s2);

O1: or_2 port map(a=> s2, b=>s3, c=>c_out);

end arc;

entity half_adder is

port (a,b : in bit ;

sum,carry : out bit);

end half_adder;

architecture arc of half_adder is

begin

sum<= a xor b;

carry <= a and b;

end arc;

entity or_2 is

port (a,b : in bit ;

c : out bit);

end or_2;

architecture arc of or_2 is

begin

c<= a or b;

end arc;

thanks bejoy ! you were very helpful indeed.

ReplyDeletethanks again buddy

iwant to become Ur friend

ReplyDeletethank u

ReplyDeletewritten in very easy language...understood very well.....thnks

ReplyDeleteif the half adder vhdl code is designed in structural style(using ex-or and and gate)then how to implement full adder in structural.

ReplyDeleteGreat help indeed! Thank you! :)

ReplyDeletethank you

ReplyDeletesuper cool...

ReplyDeletepls give the logical diagram of this code then it would be great

ReplyDeletepls give the logical diagram of the code then it would be great

ReplyDeleteThanx .. its really helpful..

ReplyDelete